Question

20 moles of A and 14 moles of B are mixed and allowed to react according to the equation:

A + 2B 3C
What is the maximum no. of moles of C which could be prepared

Answer 1

A+2B→C

That means 5 moles of A will need 10 moles of B to completely react with but we dont have that much moles of B

Now 8 moles of B will be requiring 4 moles of A to completely react with

Now, as 2 moles of B gives 1 mole of C,

8 moles of B will give 4 moles of C

or we can say that 1 mole of A gives 1 more of C

so 4 moles of A will give 4moles of C

Answer 2

Answer:

The maximum number of moles of C which could be prepared according to the balanced equation is 21.

Explanation:

In the balanced chemical equation, the number of moles of a product depends on the number of moles of the limiting reagent.

The balanced chemical equation is - A + 2B → 3C

The given values; Number of moles of A is 20, Number of moles of B is 14

The number of moles of C = ?

- According to the balanced chemical equation, 1 mole of A gives 2 moles of B

So, 20 moles of A gives 40 moles of B. But the number of moles of B is only 14.

Hence, the limiting reagent is B.

- According to the balanced chemical equation, 2 moles of B gives 3 moles of C.

So, 14 moles of B gives 21 moles of C.

Hence, the maximum number of moles of C which could be prepared is 21 moles.

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