Question

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If cot theta = 7/8 , evaluate

1) (1+sin theta ) ( 1-sin theta )/ (1+ cos theta )

2 ) cot^2 theta ​

Answer 1

Answer:

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Step-by-step explanation:

using identity (a+b)(a-b)=a^2-b^2

(1-sin^2 theta)/(1-cos^2 theta)=cos^2 theta/sin^2 theta=cot^2 theta =(7/8)^2=49/64.

2. cot theta=7/8

sin theta = 8/sqrt(113)

cos theta=7/sqrt(113)

(1+sin theta)/cos theta = (sqrt(113)+8)/7

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Answer 2

Answer:

BC = 8x and AB = 7x

Step-by-step explanation:

We will first calculate the value sin theta and cos theta . . .

Now tan theta = 1 / cos theta = 1/7/8 = 8/7

Side opp angle theta / side adjacent angle theta = 8/7

BC / AB = 8 / 7

Let BC = 8x

And AB = 7x

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