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I need the answer of Q2..
Pls I need explanation tooo..
Pls fast..
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In triangle PQO,
OP = OQ = 8cm (radius)
=> <QPO = <PQO - (1)
<POQ = 60°
<PQO + <OPQ + <PQO = 180°
From (1)
2<QPO = 180° - 60°
<QPO = 120/2 = 60°
<QPO = <PQO = 60°
=> <PQO = <OPQ = <PQO = 60°
=> triangle PQO is an equilateral triangle.
=> OP = OQ = PQ = 8cm
∴ PQ = 8cm
anshu77777:
hole it was helpful to you
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this is the correct answer
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