Question

20 POINTS | TRIGNOMETRIC RATIOS | CLASS 9 |

Answer 1

See the attached file

Answer 2

$\huge\boxed{Answer}$

(Sec O - tan O)/(Sec O + tan O) = 1/4

(1 - SinO) / (1 + SinO) = 1/4

4(1 - SinO) = (1 + SinO)

4 - 4SinO = 1 + SinO

3 = 5SinO

5SinO = 3

SinO = 3/5