20. Rutherford’s experiments suggested that the size of the nucleus is about
(a) 10-14 m to 10-12
m
(b) 10-15 m to 10-13 m
(c) 10-15 m to 10-14
m
(d) 10-15 m to 10-12
m
Answers
Explanation:
The radius of the nucleus is 10^5 times less than the radius of the atom
Answer:
10^-15 m to 10^-14 m.
Explanation:
To estimate the size of the nucleus Rutherford performed an experiment of Scattering of Alpha particle .
The potential of the particle that touches the nucleus is given as 10.4MeV. He assumed that all the K.E. lost should be equal to all the P.E. that is being gained.
K.E.lost=P.E.gained
r= 2×97e⋅4πε / 10.4MeV
r= 2×97×1.6×10^-19×8.9×10^-9 / 10.4×10^6
By solving the above equation r=3.6×10^−15 m
If the electron is stopped and turned back then the potential energy will be 7.7 MeV.
By substituting the potential in the above equation we getr= 2×97×1.6×10^-19×8.9×10^-9 / 7.7×10^-6
r=3.6×10^−14 m
As seen, size of nucleus ranges from 10^-15 m to 10^-14 m.