Question

20. Show that p-1 is a factor of p-1 and also p-11​

Answer 1

Answer:

g(1) = 1-1 = 0. So, p-1 is a factor of g(p). h(1) = (1) 11-1 = (1)^10-1 = 1-1 = 0. Hence p-1 is a factor of h(p).

Step-by-step explanation:

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Answer 2

Answer:

so girl here is your ans

You have asked to prove that (p^-1) is a factor of both p^10-1 and p^11-1

Lets see,

Assuming here that g(p) = p^10-1. H(p) = p^11-1, we try and plug in values

for p -1 in equation g(p) = p^10-1, we get

g(1) = 1^10-1 = 1-1 (as 1^10 = 1) g(1) = 1-1 = 0. So, p-1 is a factor of g(p).

Now again, we plug in p = 1 in second equation, and we get

h(1) = (1) 11-1 = (1)^10-1 = 1-1 = 0. Hence p-1 is a factor of h(p).