Question

20=
$t + {t}^{2}$


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Answer 1

Answer: $(t-4)(t+5)=0$

Step-by-step explanation:

$t+t^2=20$

$t^2+t-20=0$

$t^2+5t-4t-20=0$

$t(t+5)-4(t+5)=0$

$(t-4)(t+5)=0$

Hope it helps!!

If 't' stands for time, then t=4 since time can never be (-ve).

Answer 2

Answer:

I know the answer but why should I tell you!!!