Question

20. The present age of a man is twice that of his
son. Eight years hence, their ages will be in
the ratio 7:4. Find their present ages.​

Answer 1

Answer:

let,present age of son be x

present age of father be 2x

After 8years,

2x+8/x+=7/4

8x+32=7x+56

x=24

father's age is 48 and son's age is 24