Question

20.

There are two identical small holes 1 and 2 of equal
area of cross-section a, on the opposite sides of
tank containing a liquid of density p. The difference
in heights between the holes is h. The tank is resting
on a smooth horizontal surface. The horizontal force
required to keep the tank in equilibrium is

(1) pgha
(2) 2 pgha
(3) 4 pgha
(4) 3 pgha
​

Answer 1

Answer:

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Answer 2

The horizontal force required to keep the tank in equilibrium is:

(2) 2ρagh

• Cross-section is represented by "a".

• Density of liquid is represented by "ρ".

• Height between the hole is represented by "h".

• Now, As per the question,

F1=ρav₁²

F2=ρav₂²

• Also, F1 > F2

• Now, F=F1−F2

                   =ρa(v₂²−v₁²)

                   =ρa(2gh₂−2gh₁)

                   =2ρag(h₂−h₁)

                   =2ρagh

• Thus, to keep the tank in equilibrium, a force of 2ρagh is required.