Question

20. Two spacemen A and B are floating is gravity
free space with zero velocity relative to each
other. "A" has a mass of 120 kg and "B" has a
mass of 90kg which includes a 5 kg radio box.
"B" throws the box towards "A" with a velocity
of 2m/x and A catches it. The change in
velocity of each one is
1) VA = 11.8cm/s v B=8cm/s
2) VA = 8cm/s v =11.8cm/s
3) VA = 10cm/s 0 B=10cm/s
4) va = 9cm/s 0 B=12cm/s​

Answer 1

Answer:

Option (2) $V_A=8\text{ cm/s}, V_B=11.8\text{ cm/s}$

Explanation:

Mass of A = 120 kg

Mass of B = 85 kg

Mass of radio box = 5 kg

B throws the box towards A with velocity 2 m/s

Initial velocity of B = 0

Let final velocity of B is $V_B$

Therefore, from conservation of linear momentum

$0=2\times5-V_B\times85$

$\implies V_B=\frac{10}{85} = 0.1176 \text{ m/s}$

                                            = 11.8 cm/s

Again from conservation of linear momentum, if the velocity of A after receiving the radio box is $V_A$ then

$2\times5=V_A\times(120+5)$

$\implies V_A=\frac{10}{125} = 0.08 \text{ m/s}$

                                              = 8 cm/s

Answer 2

Answer:

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