Question

With the help of Avogadros law, show that the volume of one mole of any gas at STP is always 22.414dm^3​
plz answer fast

Answer 1

Answer:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

Standard condition of temperature (STP)  is 273 K and atmospheric pressure is 1 atmosphere respectively.  

According to the ideal gas equation:

$PV=nRT$

P = Pressure of the gas = 1 atm

V= Volume of the gas = ?

T= Temperature of the gas = 273 K      

R= Gas constant = 0.0821 atmL/K mol

n=  moles of gas= 1

$V=\frac{nRT}{P}=\frac{1\times 0.0821\times 273}{1}=22.4L$

Thus at STP one mole of gas occupies a volume of 22.4 liters.