Question

20 x square - 20 X + 8

Answer 1

$20x^{2} - 20x + 8$

$= 4(5x^{2} - 5x + 2)$

$b^{2} - 4ac < 0$

Thus it won't have any real roots.

Applying the quadratic formula gives you $x = \frac{5 + i\sqrt{15} }{10}$

or $x = \frac{5 - i\sqrt{15} }{10}$