Question

20/y + 8/x = 1 and 18/y + 9/x= 1 solve for 'x' and 'y' by elimination method

Answer 1

Answer: y=(-54)

x=27/4

Step-by-step explanation:

20/y + 8/x =1.......eq.1

18/y + 9x =1.........eq.2

Let 1/y be a and 1/x be b

Then eq.1 becomes:

20a+8b=1

And eq.2 becomes:

18a+9b=1

We can further reduce eq.1 as:

5a+4b=1/2 ......eq.3

And eq.2 as:

2a+b= 1/9....eq.4

Multiplying eq.4 by 4

We get :8a+4b=4/9......eq.5

Using elimination method in eq.3 and eq.5..

=>5a+4b=1/2

=>8a+4b=4/9

=>(-) (-) (-) [Changing signs of lower eq.]

=>We get: -3a=1/18

a= -1/54

Putting the value of a in eq.4

We get: 2a+b=1/9

=>2 (-1/54)+b =1/9

=>-1/27 + b=1/9

=> b= 1/9 + 1/27

b= 4/27

So; 1/y = -1/54

And y=( -54)

Thus: x = 27/ 4

Hope it helps you✌✌