Question

20 years ago a father was four times the age of his son. After four years from now the age pf the son will be half of the age of father . find the present ages of father and son​

Answer 1

Father's present age = 68 years, Son's present age = 32 years

Step-by-step explanation:

Let father's present age be x and son's present age be y.

According to the problem,

(i) (x-20) = 4(y-20)

4y-x = 60

(ii) x+4 = 2(y+4)

x-2y = 4

Solving the two equations, we get:

x=68

y=32

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20 years ago a father was four times the age of his son. After four years from now the age pf the son will be half of the age of father . find the pre

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