Question

20 years ago, the ages of father was 5 times the age of son. At present, fathers age is 10 years
more than twice his son's age find their
present ages.(with steps plzzz)​

Answer 1

Let the present age of the son be x.

Father's present age = 2x+10_____1

20 years ago

Son's age = x-20

Father's age = 5(x-20) = 5x-100 _____2

Adding 20 years to eq2

5x-100+20 = 5x-80______3

Equating eq2 and eq3

5x-80 = 2x +10

5x-2x = 10 + 80

3x = 90

x = 90/3

x = 30

Son's present age = x = 30 years

Father's present age = 2x+10 = 2×30+10 = 70 years