200 g of ice at 0degree Celcius converts into water at 0degree Cecius in 1 minute when heat is supplied to it at a constant rate. In how much time 200g of water at 0degree Celcius will change to 20degree Celcius? Take specific latent heat of ice=336 J g-1.
Answers
Answered by
217
Mass(m) = 200 gm
= 2/10 kg
Time(t) = 60 sec
Latent heat of fusion(L) = 336 * 10³ J/kg
Specific heat capacity (c) = 4200 J/kg.K
Heat gained = m * L
= 2/10 * 336 * 10³
= 67200 J
Work done = Energy consumed
Work done = 67200 J
Power = Work/Time
= 67200/60
= 1120 J/s
Heat required = m * c * ∆t
= 2/10 * 4200 * (20-0)
= 16800 J
Work done = Energy consumed
Work done = 16800 J
Time = Work/Power
= 16800/1120
= 15 sec
If it helped, mark it as brainliest.
Follow me to get the most simplified answers for your questions.
= 2/10 kg
Time(t) = 60 sec
Latent heat of fusion(L) = 336 * 10³ J/kg
Specific heat capacity (c) = 4200 J/kg.K
Heat gained = m * L
= 2/10 * 336 * 10³
= 67200 J
Work done = Energy consumed
Work done = 67200 J
Power = Work/Time
= 67200/60
= 1120 J/s
Heat required = m * c * ∆t
= 2/10 * 4200 * (20-0)
= 16800 J
Work done = Energy consumed
Work done = 16800 J
Time = Work/Power
= 16800/1120
= 15 sec
If it helped, mark it as brainliest.
Follow me to get the most simplified answers for your questions.
Similar questions