Question

200 g of water at 30°C is mixed with an equal amount of water at 60°C. Then resultant temperature
of the mixture is​

Answer 1

Answer:

Explanation:

Thus the resultant temperature of the mixture is 45°C.

Explanation:

Given data:

Mass of water "m"= 200 g

Initial temperature "T" = 30°C

Mass of water m' = 200 g

Second temperature = 60°C

Formula:

Delta Q = (m1 x T1 ) + (m2 + T2) / total mass

Delta Q =  (200 g x 30) + (200 x 60 ) / 400

Delta Q = 6000 + 12000 / 400

Delta q = 45°C

Thus the resultant temperature of the mixture is 45°C

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