200 gram is subjected to a force of 0.3 ICAP - 0.4 J cap Newton's if the body starts from rest its displacement is 6 seconds is
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Answer:
Explanation:Correct option is
A
(9
i
∧
−12
j
∧
)
Force acting on an object =
F
=
dt
d
p
⟹Δ
p
=∫
0
t
F
dt
⟹
p
f
−0=(0.3
i
^
−0.4
j
^
)×6kgm/s
⟹
v
f
=(9
i
^
−12
j
^
)N
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