Question

200 grams of a soil is taken and dried completely in bright sunshine. The mass of dried soil is found to be 170 grams. Calculate the percentage of water or moisture present in the given sample of soil.​

Answer 1

Answer:

15 percent

Explanation:

since the mass of dry soil is 170 g, moistrous soil= 200-170= 30 g

Hence the percentage = 30/200 × 100 = 15%

Answer 2

Given:

Mass of wet soil sample = 200 grams

Mass of dry soil sample = 170 grams

To find:

Percentage of water content or moisture content in the given sample=?

Solution:

The moisture content of soil is the amount of water soil has retained within.

It can be calulated in the following steps:

Step 1: Calculate the mass of water in the soil sample

Mass of water = Mass of wet soil - Mass of dry soil

                       = 200 grams- 170 grams

                       = 30 grams

Step 2: Apply the formula to calculate moisture content

Moisture content = $\frac{Mass of wet soil - Mass of dry soil}{Mass of wet soil}$× 100

Moisture content = $\frac{30}{200}$ grams × 100

Moisture content = 15%

Hence, the percentage of water in the given soil sample is 15%.