Question

200 J of work is done in sliding a 2kg block up an inclined plane through a height of 10 m
Work done against friction is​

Answer 1

Work done against gravity = m * g * h

= 2 * 10 * 10 [ g = 10 m/s ]

= 200 J

Actual work done = 200 J

Work done against friction = 200 J - 200 J

= 0 J