200 m in 40
displacement at the end of 2 min
2 Joseph jogs from one end A to the other end
300 m road in 2 minutes 30 seconds and the
and jogs 100 m back to point C in another 1 n
Joseph's average speeds and velocities in jogg
B and (b) from A to C?
ates the a
Answers
Correct Question :
Joseph jogs from one end A to the other end B of a straight road 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another 1 minute . What are Joseph's average speeds and velocities in jogging :
a) from A to B?
b) from A to C?
Solution :
We will first draw a line diagram to show the movement of Joseph during jogging. Refer to the attachment.
a) Average speed and velocity from A to B
• Total distance from A to B = 300 m
• Total time taken from A to B = 2 minutes 30 seconds
→ 2 × 60 seconds + 30 seconds
→ 120 seconds + 30 seconds
→ 150 seconds
★ Average Speed = Total Distance Covered/ Total time taken
→ Average Speed =
→ Average Speed = 2 m/s
While travelling from A to B, displacement is also 300 m and the time taken is also 150 s
★ Average Velocity = Displacement/ Total time taken
→ Average Velocity =
→ Average Velocity = 2 m/s
When Joseph jogs from A to B, average speed and velocity,both are equal in magnitude each being 2 m/s
b) Average speed and velocity from A to C
• Total distance from A to C = 300 m + 100 m
→ 400 m
• Total time taken from A to B = 2 minutes 30 seconds + 1 minute
→ 2 × 60 seconds + 30 seconds + 60 seconds
→ 120 seconds + 30 seconds + 60 seconds
→ 210 seconds
★ Average Speed = Total Distance Covered/ Total time taken
→ Average Speed =
→ Average Speed = 1.9 m/s
While travelling from A to C, displacement is (300 - 100) = 200 m and the time taken is also 210 s
★ Average Velocity = Displacement/ Total time taken
→ Average Velocity =
→ Average Velocity = 0.95 m/s
When Joseph jogs from A to C, average speed is 1.9 m/s and average velocity is 0.95 m/s
![](https://hi-static.z-dn.net/files/d8d/2e0831ee8f042dcb6728da2bc24a6ec5.jpg)