200 ml NH3 is 50% decomposed find the total rise or decrease in total volume
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Explanation:
Identify the limiting reactant
We can use partial pressures as a replacement for moles because
P
∝
n
.
m
m
m
m
m
m
N
2
m
+
m
3H
2
→
2NH
3
P
(atm):
m
l
l
2.73
m
m
m
2.73
Divide by:
m
l
l
1
m
m
m
m
l
3
Moles rxn:
l
l
2.73
m
m
m
0.910
Hydrogen is the limiting reactant because it gives the fewest moles of reaction,
Step 2: Calculate the partial pressures after the reaction
m
m
m
m
m
m
N
2
m
+
m
3H
2
→
2NH
3
I:/atm:
m
l
m
2.73
m
m
m
2.73
m
m
l
l
0
C:/atm:
m
l
-0.910
m
m
l
-2.73
m
l
+1.82
E:/atm:
m
m
1.82
m
m
m
m
0
m
m
l
l
1.82
The product mixture will contain ammonia and unreacted nitrogen, each with a partial pressure of 1.82 atm.
P
total
=
P
N₂
+
P
NH₃
=
1.82 atm + 1.82 atm
=
3.64 atm
P
NH₃
=
1.82 atm
.
Step 4. Now let the cylinder contract and calculate the new volume.
Remember that we are using partial pressures as a substitute for moles
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