Question

200 ml of 0.1 M HCl is treated with 1.0g of pure CaCO3. What would remain after the reaction? * 1 point a)0.5g of CaCO3 b)10 milliequivalents of free HCl c)Neither of the above two d)0.25g of CaCO3 & 1 milliequivalent of HCl​

Answer 1

c right answer hai doston waah kya