Question

200 ml, of a solution contains 5.85g dissolved 1 Sodium chloride. The concentration of the
solution will be (Na-23; C1-35.5)
)
1) I molar 2) 2 molar 3) 0.5 molar 40,25 molar​

Answer 1

Answer:

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Explanation:

Molarity, M= number of moles/volume of solution

M= nV\frac{n}{V}

V

n

Number of moles, n= mass/molar mass

Molar mass of NaCl=58.5 g/mol

Mass = 5.85g

n=5.85/58.5=0.1 mol

Volume, V=500 mL=0.5 L

∴M=0.1/0.5=0.2mol/L

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Answer 2

Answer:

Explanation:

5.85/58.5

=0.1

Again 200/1000=0.2l

Then , 0.1/0.2=0.5M