Physics, asked by rkvidhurirk88, 9 months ago

200 NM light is incident what will be the maximum kinetic energy of photoelectrons emitted from caesium work function is equal to 1.9 EV planck constant is equal to 6.63 into 10 power minus 34 speed of light is equal to 3 into 10 ki power minus 8

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Answered by 9672shraj

Have a look at the pic

It's based upon photoelectric effect

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