Math, asked by Anonymous, 1 year ago

2001^2001-2001^2000/2001^2000-2001^1999???? please tell it'S value.

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Answered by rohitkumargupta
22
[ 2001^(2000 + 1) - 2001^(2000) ] / [ 2001^(2000) - 2001^(2000 - 1) ]



2001^2000 [ 2001 - 1] / 2001^2000 [ 1 - 1/2001 ]


[ 2000] / [ (2000)/2001 ]

 
 = 2001




 
I HOPE ITS HELP YOU,
THANKS
Answered by tamilinians
1

Answer:

[ 2001^(2000 + 1) - 2001^(2000) ] / [ 2001^(2000) - 2001^(2000 - 1) ]

2001^2000 [ 2001 - 1] / 2001^2000 [ 1 - 1/2001 ]

[ 2000] / [ (2000)/2001 ]

 

= 2001

I HOPE ITS HELP YOU,

THANKS

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