2001^2001-2001^2000/2001^2000-2001^1999???? please tell it'S value.
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[ 2001^(2000 + 1) - 2001^(2000) ] / [ 2001^(2000) - 2001^(2000 - 1) ]
2001^2000 [ 2001 - 1] / 2001^2000 [ 1 - 1/2001 ]
[ 2000] / [ (2000)/2001 ]
= 2001
I HOPE ITS HELP YOU,
THANKS
2001^2000 [ 2001 - 1] / 2001^2000 [ 1 - 1/2001 ]
[ 2000] / [ (2000)/2001 ]
= 2001
I HOPE ITS HELP YOU,
THANKS
Answered by
1
Answer:
[ 2001^(2000 + 1) - 2001^(2000) ] / [ 2001^(2000) - 2001^(2000 - 1) ]
2001^2000 [ 2001 - 1] / 2001^2000 [ 1 - 1/2001 ]
[ 2000] / [ (2000)/2001 ]
= 2001
I HOPE ITS HELP YOU,
THANKS
Step-by-step explanation:
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