Question

plz answer i mark as brainlist plz answer 15,16,17

Answer 1

sin 3θ = cos (θ - 6°)
cos (90° - 3θ) = cos (θ - 6°)
90° - 3θ = θ - 6°
 θ + 3θ = 90° + 6°
4θ = 96°
θ = 24°

sec4A = cosec(A-20)
sec4A = sec(90-(A-20))  [sec(90-x) = cosecx]
sec4A = sec(110-A)
4A = 110-A
5A = 110
A = 22

Sec2A = cosec(A-42)
cosec(90-2A) = cosec(A-42)
90-2A = A-42
132 = 3A
A = 132/3 = 44 degree

Answer 2

Heya !!

Here's your answer..
_________________

sin 3θ = cos ( θ - 6 )
cos ( 90-3θ ) = cos ( θ - 6 )
90 - 3θ = θ - 6
90 + 6 = θ + 3θ
96 = 4θ
θ = 96/4
θ = 24
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sec 4A = cosec ( A - 20 )
cosec ( 90 - 4A ) = cosec ( A - 20 )
90 - 4A = A - 20
90 + 20 = A + 4A
110 = 5A
A = 110/5
A = 22
____________________

sec 2A = cosec ( A - 42 )
cosec ( 90 - 2A ) = cosec ( A - 42 )
90 - 2A = A - 42
90 + 42 = A + 2A
132 = 3A
A = 132/3
A = 44
___________________

Hope it helps..
Thanks :)