200ml N/10 H2SO4 is mixed into 300ml N/100NaOH. calculate normality of resulting mixture.
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Answer:
0. 046N
Explanation:
- NV =n1v1+n2v2
- Data :
- v1=200ml
- v2=300ml
- n1=N/10= 0. 1N
- N2=N/100=0. 01N
- V=v1+v2=200+300=500ml
- Now put the data in above formula
- N×500=0. 1×200+0. 01×300
- 500N=20+3
- N=23/500
- N=0. 046N
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