Question

200ml of 3M AgNo3 and 300ml of 2m AgNo3 are added to a solution containing 200ml of 10M NaCl. The amount of NaCl left unprecipitated is

Answer 1

Hope this helps you.

Answer 2

Answer:

Explanation:

3*200+2*300=M*500

M=1200/500

M=22/5

AgNO3+NaCl ----> AgCl +NaNO3

no. of moles of AgNO3=12/5*500/1000 = 1.2mole

no. of moles of NaCl =10*200/1000 =2 mole

here the given amount of AgNO3 is totally consumed ,so it is the limiting

reagent.

amount of NaCl left=0.8* 51.5

=46.8g

Hope it helps !