Question

200ml of aqueous solution contain 18g of glucose.the osmotic pressure of the solution at 27°c will be(molar mass of glucose=180g/mol)​

Answer 1

Answer:

18 g is equal to 18/180 i.e. 0.1 mole

Vol = 200ml = 0.2 dm^3

T= 27° C = 27 +273 = 300 K

osmotic pressure π = CRT

C = concentration i.e mol of solute/ vol of solution

C = 0.1/ 0.2= 1/2

R = 8.314

π = 8.314 * 300 * 1/2

π = 1247.1 Pa

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Answer 2

Explanation:

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