Question

200ml of water sample has hardnhardness equivalent of 25 ml of 0.08 N MgSO4 .What is the hardness in ppm

Answer 1

The hardness of water is 500ppm.

GIVEN

Volume of water = 200ml

volume of MgSO₄ = 25ml

Normality of MgSO₄ = 0.08N.

TO FIND

Hardness of water in ppm

SOLUTION

We can simply solve the above problem as follows-

Volume of water = 200ml

Density of water = 1 gm/ml

Mass = volume × density

Mass = 200 × 1 = 200 grams.

We know that,

Number of grams equivalent = number of grams equivalent of CaCO₃

Number of Gram equivalent = Normality × volume

Mili equivalent of MgSO₄ = 0.08×25 = 2

We know that,

Mili equivalent = weight /equivalent weight

Weight of CaCO3 = 2×100/1000×2 = 0.1 gram.

Hardness of water =

weight of CaCO₃×10⁶/weight of water

$\frac{0.1 \ \times {10}^{6} }{200}$

= 500 ppm

Hence, The hardness of water is 500ppm.

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