Question

factorise the following L2-(m-n)2​

Answer 1

Answer:

take 2 common

Step-by-step explanation:

2[ L-m+n ]

this the Answer

Answer 2

The factorisation of $l^2-(m-n)^2$ is equal to ( l + m - n)( l - m + n).

Step-by-step explanation:

We have,

$l^2-(m-n)^2$

To find, the factorisation of $l^2-(m-n)^2$ = ?

∴ $l^2-(m-n)^2$

Using the algebraic identity,

$a^{2}-b^{2}=(a+b)(a-b)$

= [ l + (m - n)][ l - (m - n)]

= ( l + m - n)( l - m + n)

∴ The factorisation of $l^2-(m-n)^2$ = ( l + m - n)( l - m + n)

Thus, the factorisation of $l^2-(m-n)^2$ is equal to ( l + m - n)( l - m + n).