Question

201,198,195,192,..., Determine if the given sequences represent an AP, assuming that the pattern continues. If it is an AP, find the nth term.

Answer 1

201, 198 , 195. 192 .........

here first term , a = 201

common difference , d = 198 - 201 = -3

now use formula, Tn = a + (n - 1)d

= 201 + (n - 1) × (-3)

= 201 - 3n + 3

= 204 - 3n

hence, nth term , Tn = 204 - 3n

Answer 2

Hello,

sequence is 201,198,195,192,...,

as we know that if it is an AP then a = 201

and the difference between two consecutive terms are equal and denoted as d.

198-201 = -3

195-198 = -3

192-195 = -3

so given sequence is AP with a = 201 d = -3

nth term of AP : Tn = a+(n-1) d

Tn = 201 +(n-1)(-3)

Tn = 201 +3 -3n = 204 -3n

Tn = 204 - 3n

Hope it helps you