Question

(201)² algebraic identity

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Answer 1

Answer:

$= {(201)}^{2}$

$= {(200 + 1)}^{2}$

${(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy$

$= {(200)}^{2} + {(1)}^{2} + 2(200)(1)$

$= 40000 + 1 + 400$

$= 40401$

Step-by-step explanation:

Hope it helps you out.....

Answer 2

(201)²=(200+1)². (a= 200,b=1)

=200²+2(200)(1)+1²

=40000+400+1

=40401

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