Math, asked by goodygal8745, 11 months ago

2018^2019+ 2019^2018( mod7)

Answers

Answered by thomassmith
1

Answer:3 mod7

Step-by-step explanation:

2018【2019】=6×336+2【3】

2018//2019=7×288+2//3

FERMAT LITTLE THEOREM →

2019^6≡2018^6≡1 MOD 7

∴2019^2018+2018^2019

≡2019³+2018²(MOD 7)

=(288*7+3)³+(288*7+2)²

≡3³+2²

≡(28-1)+4

≡ 3 MOD 7

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