2018^2019+ 2019^2018( mod7)
Answers
Answered by
1
Answer:3 mod7
Step-by-step explanation:
2018【2019】=6×336+2【3】
2018//2019=7×288+2//3
FERMAT LITTLE THEOREM →
2019^6≡2018^6≡1 MOD 7
∴2019^2018+2018^2019
≡2019³+2018²(MOD 7)
=(288*7+3)³+(288*7+2)²
≡3³+2²
≡(28-1)+4
≡ 3 MOD 7
Similar questions