Question

2092
21:4
AB²
Smp
(ICSE 20 , 9
22. ABC is a right angled triangle with ZABC = 90°. D
is any point on AB and DE is perpendicular to AC.
Prove that:
ADE is similar to ACB
Fig. 12.126
(i) AADE – AACB
(ii) If AC = 13 cm, BC = 5 cm and AE = 4 cm. Find
DE and AD
(iii) Find, area of AADE: area of quadrilateral BCED.
(ICSE 2015)​

Answer 1

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