20cc of 1M HCl, 30cc of 0.5N H2SO4 and 50 cc of 0.2 NHNO3 are mixed together.
What will be the normality of the final solution?
Answers
normality of the final solution is 0.36N
It has given that,
- 20cc of 1M HCl
- 30 cc of 0.5 N H₂SO₄
- 50 cc of 0.2N HNO₃
total volume of mixed solution , V = V₁ + V₂ + V₃
= 20cc + 30cc + 50cc = 100cc
normality of HCl = molarity × n - factor
= 1M × 1 = 1N
here, N₁ = 1N, N₂ = 0.5N , N₃ = 0.2N
now using formula, N_fV = N₁V₁ + N₂V₂+ N₃V₃
⇒N_f × 100cc = 1N × 20cc + 0.5N × 30cc + 0.2N × 50cc
⇒N_f × 100cc = (20 + 6 + 10)Ncc
⇒N_f = 36/100 = 0.36 N
therefore normality of the final solution is 0.36N
Answer:
normality of the final solution is 0.36N
It has given that,
20cc of 1M HCl
30 cc of 0.5 N H₂SO₄
50 cc of 0.2N HNO₃
total volume of mixed solution , V = V₁ + V₂ + V₃
= 20cc + 30cc + 50cc = 100cc
normality of HCl = molarity × n - factor
= 1M × 1 = 1N
here, N₁ = 1N, N₂ = 0.5N , N₃ = 0.2N
now using formula, N_fV = N₁V₁ + N₂V₂+ N₃V₃
⇒N_f × 100cc = 1N × 20cc + 0.5N × 30cc + 0.2N × 50cc
⇒N_f × 100cc = (20 + 6 + 10)Ncc
⇒N_f = 36/100 = 0.36 N
therefore normality of the final solution is 0.36N