Question

একটি খেলনা গাড়ি 20cm/s বেগে চলছিল। 1 metre দূরত্ব যাওয়ার পর ওই গাড়ির বেগ হল 50cm/s। ত্বরন কত?

Answer 1

Answer:

Initial speed of the car, u = 20 cm/s = 0.2 m/s

Final speed of the car, v = 50 cm/s = 0.5 m/s

Distance covered before stopping, d = 1 m

To find,

Acceleration of the car.

Solution,

The change in velocity divided by time equals acceleration. The mathematical form is given by :

a=\dfrac{v-u}{t}a=

t

v−u

Using third equation of motion,

\begin{gathered}v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(0.5)^2-(0.2)^2}{2\times 1}\\\\a=0.105\ m/s^2\end{gathered}

v

2

−u

2

=2ad

a=

2d

v

2

−u

2

a=

2×1

(0.5)

2

−(0.2)

2

a=0.105 m/s

2

So, the acceleration of the car is 0.105\ m/s^20.105 m/s

2

.