20litres decreased by 45 precent
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Given:
(i) The amount of petrol present is 20L.
To find:
(i) The amount of petrol present when it is decreased by 45%
Solution:
We know that
If a quantity having x litres of substance is decreased by y%, then the amount of substance left in it would be equal to
[(100-y)% of x] litres
Similarly, after reducing 45% from 20L, we have
[(100-45)% of 20] L
= (55% of 20)L
= (55*20/100) L
= 11L
So, 11L of petrol is left.
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