A person C can complete 21% of work in 10 days while working with 233 1/3% of his efficiency. B is 11 1/9% more efficient than C. A while working with his half efficiency can complete the work in half time as compared to the taken by B. Find the time taken by A & B together to complete the 50% of whole work ?
Answers
Given : person C can complete 21% of work in 10 days while working with 233 1/3% of his efficiency.
To find : time taken by A & B together to complete the 50% of whole work
Solution:
person C can complete 21% of work in 10 days while working with 700/3 % efficiency
=> person C can complete 100% of work with 7/3 efficiency in 10 * 100/ 21 days = 1000/21 days
person C can complete 100% of work with normal Efficiency = (1000/21) * 7/3
= 1000/9 days
=> C 's 1 day work = 9/1000
B is 11 1/9% more efficient than C => 100/9 % efficient = 1/9 more efficient
B's 1 Days work = 9/1000( 1 + 1/9) = (9/1000)(10/9) = 1/100
=> B can complete work in 100 Days
A with half efficiency can complete in 50 Days
A with full efficiency will take 25 Days to complete
time taken by A & B together to complete the 50% of whole work in d days
d(1/100 + 1/25 ) = 1/2
=> d (5/100) = 1/2
=> d = 10
10 Days time taken by A & B together to complete the 50% of whole work
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The person B can do the whole job is 16 days.
Step-by-step explanation:
A can do the job in 24 days.
The job A can do in a day =1/24
B is 50% more efficient than A.
The job B can do in a day = (1 / 24) x 150 / 100
The job B can do in a day = 150 / 2400 = 1 / 16
So, B can do the whole job in 1 / (1 / 16) = 16 days
Thus B can do the whole job is 16 days.