20ml of 2N acid solution is mixed with 8ml of 2.5N alkali solution & whole is diluted to 100ml with water. Calculate normality of the resulting solution?
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Answer:
Given Normality of HCI = 0.1 N,
Volume of HCl = 100 ml
Normality of NaOH = 0.2 N,
Volume of NaOH = 100 ml
∴ Miliequivalents of HCl =0.1×100=10
∴ Miliequivalents of NaOH =0.2×200=20
HCl+NaOH→NaCl+H
2
O
Miliquivalents before reaction 10 20 0 0
Milliequivalents after reaction 0 10 10 10
No. of moles left in solution = 20 - 10 = 10
Normality of resulting solution =
Total volume of solution
No. of moles left in solution
=
100+100
10
=
200
10
=0.05N
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