Question

20ml solution containing 0.1 molarity each of HCL and HNO3 required X ml of 0.1 molarity NaOH and for complete neutralization in another experiment to 20ml of original solution excess of agno3 is added and the PPT of agcl is filtered of the entire filtrate along with washings required by y ml of same NaOH solution for neutralization. expression between x and y ​

Answer 1

Answer:

Explanation:

equivalent of hno3+ equivalent of hcl

let volume of hno3 be t

and volume of hcl = 20-t

equivalent = 2

equivalent of naoh = 0.1x

equivalent remaining = 2-0.1x

for 20+x = 2-0.1x

for 20 ml be s equivalents

40-2x / 20+x = s

equivalent of agcl = 40-2x / 20+x

equivalent of naoh = 40-2x / 20+x

0.1y=40-2x / 20+x

y=400-20x / 20+x