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if <A ‹ <B then 1/2×<A ‹ 1/2 ×<B
so in triangle OAB OA side is greater than OB side(side opposite to larger angles are larger)
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According to the triangle theorem.
Side opposite to smallest angle is largest and side opposite to greatest angle is smallest.
Here,<B><A
THEREFORE side opposite to<A is greatest.
Hence. Proved that OA>OB
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