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the velocity time graph of car A and B which start from same place and along a straight road in same direction is shown below.
calculate
(a) accelaration of car B between 2sec and 4 secs.
(b) the time at which both cars have same velocity.
(c)the distance travelled by two cars A and B in 8sec.
(d) which of the two cars is ahead of after 8sec and by how much?
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(a) acceleration of a car b from 2-4
T=2
V=60
U=20
Acceleration = v-u/t
40/2=20
(b) after 2 and 6 sec
(c) distance travelled = v/t
80/8=10m
(d)car A is ahead
T=2
V=60
U=20
Acceleration = v-u/t
40/2=20
(b) after 2 and 6 sec
(c) distance travelled = v/t
80/8=10m
(d)car A is ahead
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here is the answer..hope it helps.
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thank
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