the foot of a ladder rests against a wall and its top is held by a rope tie.. the ladder weighs 100n and center of gravity is 0.40m length from the foot. a 150 n child hungs from a rung that is 0.20 of length from the top. determine the tension in the tie rope and the components of forces on the foot of the ladder
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Completing Question : Length of ladder 1m
Angle made by ladder with the vertical is (theta) .
Final Answer :
160 \tan( \theta) \: units160tan(θ)units
Horizontal Component of force acting on the foot of ladder : = Tension of rope
Vertical Component : 250N
Steps and Understanding :
1) System is in Equilibrium,
So Net Torque about any point is 0 .
2) Let that point be Foot of ladder.
There are forced which are giving torque to ladder.
Tension
Force applied by Child
Gravitational force.
3) We will make out ne+ torque 0 to find the value of Tension.
For Calculation see pic.
Angle made by ladder with the vertical is (theta) .
Final Answer :
160 \tan( \theta) \: units160tan(θ)units
Horizontal Component of force acting on the foot of ladder : = Tension of rope
Vertical Component : 250N
Steps and Understanding :
1) System is in Equilibrium,
So Net Torque about any point is 0 .
2) Let that point be Foot of ladder.
There are forced which are giving torque to ladder.
Tension
Force applied by Child
Gravitational force.
3) We will make out ne+ torque 0 to find the value of Tension.
For Calculation see pic.
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