Question

20x2 – 130x = –200 solve the quadratic equations
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Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

20x^2-130x=-200

We move all terms to the left:

20x^2-130x-(-200)=0

We add all the numbers together, and all the variables

20x^2-130x+200=0

a = 20; b = -130; c = +200;

Δ = b2-4ac

Δ = -1302-4·20·200

Δ = 900

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

x1=−b−Δ√2ax2=−b+Δ√2a

Δ−−√=900−−−√=30

x1=−b−Δ√2a=−(−130)−302∗20=10040=2+1/2

x2=−b+Δ√2a=−(−130)+302∗20=16040=4