Question

20y2 + 3y - 2 Please Factor completely

Answer 1

Answer:

y= 1/4 , (-2)/5

Step-by-step explanation:

20y^2 + 3y - 2 = 0

Split middle term as

8y and -5y because their product = product of first term and second term

and if we add them it is equal to middle term

So,

(20y^2 -5y)+(8y-2)

Take out common

5y(4y-1) 2(4y-1)

(4y-1) (5y+2)

Equal them to zero

4y-1 = 0

y=1/4

5y+2=0

y= -2/5

So, y= 1/4 , (-2)/5

Hope it helps you,

Manikanta Bharatula,

Thank you.