Question

With usual notation of triangle abc. If angle b =pi/2 and a-b+c is equal to

Answer 1

Answer:

$\huge{\pink{\boxed{\green{\sf{\therefore\angle a - \angle b + \angle c = 0 \degree}}}}}$

Step-by-step explanation:

$\huge{\pink{\boxed{\green{\underline{\red{\sf{SOLUTION-}}}}}}}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: {\orange{given}} \\ { \pink{ \boxed{ \green{ \angle b = \frac{\pi}{2} = \frac{180 \degree}{2} = 90 \degree }}}} \\ \\ \: \: \: \: \: \: \: { \blue{to \: find}} \\ { \purple{ \boxed{ \red{ \angle a - \angle b + \angle c = ? }}}}$

☆ According to given question:

☆ We know that sum of all angles of a triangle is 180°.

☆ So we have one angle that is angle b.

$\to \angle a + \angle b + \angle c = 180 \degree \\ \to \angle a + 90 \degree + \angle c = 180 \degree \\ \to \angle a + \angle c = 180 \degree - 90 \degree \\ \to \angle a + \angle c = 90 \degree - - - - - (1) \\ \\ \to \angle a - \angle b + \angle c \\ \to \angle a - 90 \degree+ \angle c \\ \to \angle a + \angle c - 90 \degree \\ \to 90 \degree - 90 \degree \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: (from(1))\\ \to 0 \degree \\ \\ { \pink{ \boxed{ \green{\therefore\angle a - \angle b + \angle c = 0 \degree}}}}$

_________________________________________

Answer 2

Answer:

The value of the angles ∠a - ∠b + ∠c = 0°.

Step-by-step explanation:

Given,

∠b = pi/2 = 90°

To find,

∠a - ∠b + ∠c

Concept,

angle sum property of triangle: In a triangle sum of all the angles is equal to 180°.

i.e. If A, B, and C are the edges of the triangle, then:

∠a + ∠b + ∠c = 180°

Calculation,

As ∠b = 90°

Then,

From the angle sum property of the triangle,

∠a + ∠b + ∠c = 180°

⇒ ∠a + 90° + ∠c = 180°

⇒ ∠a + ∠c = 90°

then from question,

∠a - ∠b + ∠c

= ∠a + ∠c - ∠b

= 90° - 90°

= 0°

Therefore, the value of the angles ∠a - ∠b + ∠c = 0°.

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