Question

20years ago a father was four times as old as his son and after 4years he will be twice as old as his son.What are their present ages?​

Answer 1

Answer:

let the age of father and son be x and y

x-20=4(y-20)

x-20=4y-80

x+80-20=4y

x+60=4y

x-4y=-60. 1 equation

x+4=2(y+4)

x+4=2y+8

x-2y=4. 2 equation

now solve it by elimination method or substiution method