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A truck driver travelling at 36 km/h sees the traffic ligh
red at the intersection. If his reaction time is 0.6 s and
retards at 6 m/s2, then distance travelled by truck befc
stopping is
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Answer:
i 36.6km/s2 is answer
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Given:
Speed of the truck = 36 km/hr
Reaction time = 0.6 sec
Retardation = 6 m/s²
Final velocity v = 0
To find:
The distance travelled by the truck before stopping.
Solution:
First we shall convert the values in S.I units:
36 km/hr = 36*5/18 m/s = 10 m/s
From the formula:
S= ut + 1/2at²
Distance travelled when the truck was not decelerated (before reaction time started):
S = ut, as a=0
S = 10*0.6 = 6 m
Distance travelled after reaction time has started:
v² = u² + 2as
Putting the values we get:
0 = 10² - 2*6*S
S = 100/12 = 8.33 m
Total distance travelled = 6 + 8.33 = 14.33 m
Therefore the distance travelled by the truck will be 14.33 m.
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